Question

The lengths of the diagonals
of a rhombus are 16 cm and 12 cm. then the
length of side
rhombus is

​

Answer 1

Answer:

10cm

Step-by-step explanation:

⇒ Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒  We know that the diagonals of rhombus bisect at right angles.

⇒  AO=  

2

16

​  

=8cm

⇒  BO=  

2

12

​  

=6cm

⇒  In right angled △AOB,

By using Pythagoras theorem,

⇒  AB  

2

=AO  

2

+BO  

2

 

⇒  AB  

2

=8  

2

+6  

2

 

⇒  AB  

2

=64+36

⇒  AB  

2

=100

⇒  AB=  

100

​  

 

⇒  AB=10cm

∴  Side of a rhombus is 10cm.

Answer 2

Answer:

24

Step-by-step explanation:

area of rhombus = 1/2 * diagonal1 * diagonal2

                            = 1/2 * 16 * 12

                            = 96

therefore each side is,

4s = 96

s=24