Question

The lengths of the diagonals of a rhombus are 16 cm. and 12 cm. respectively. Find the
length of its sides.
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Answer 1

Answer:

$We \: know \: diagonals \: of \: rhombus \: bisect \: each \: other \: at \: right \: angles. \\ </p><p>So, \: OA = OC = \frac{1}{2} AC = \frac{1}{2} \times 16 = 8 \: cm \\ </p><p>And \: OB = OD = \frac{1}{2} BD = \frac{1}{2} \times 12 = 6 \: cm</p><p> \\ In \: right \: triangle \: OAB \\ </p><p> {OA}^{2} + </p><p> {OB}^{2} = {AB}^{2} \\ = {8}^{2} + {6}^{2} \\ = 64 + 36 \\ = 100 \\ = {10}^{2} \\ AB = 10 \: cm</p><p>$

So length of each side of rhombus = 10 cm

Answer 2

Answer:

this is correct..............................