The lengths of the diagonals of a rhombus are 16 cm and 12 cm. then, find the length of the side of the rhombus.
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Let ABCD be a rhombus with AC and BD as its diagonals.
We know that the diagonals of a rhombus bisect each other at right angles.
Let O be the intersecting point of both the diagonals.
Let AC=12cm and BD=16cm
OA=AC/2
OA= 12/2=6cm
OB=BD/2
OB=16/2=8cm
In rt.ΔAOB by Pythagoras theorem we have
AB²=OA²+OB²
=(6)²+(8)²
=36+64
=100
AB=10cm
Hence, each side of the rhombus is of length 10cm
We know that the diagonals of a rhombus bisect each other at right angles.
Let O be the intersecting point of both the diagonals.
Let AC=12cm and BD=16cm
OA=AC/2
OA= 12/2=6cm
OB=BD/2
OB=16/2=8cm
In rt.ΔAOB by Pythagoras theorem we have
AB²=OA²+OB²
=(6)²+(8)²
=36+64
=100
AB=10cm
Hence, each side of the rhombus is of length 10cm
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Answer:
10 cm is your answer
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