Question

The lengths of the diagonals of a rhombus are
16 cm and 30 cm. Then, the perimeter
of the rhombus is ........ cm.
​

Answer 1

Answer =>

Perimeter = 68 cm .

Rhombus =>

• All sides are equal
• Diagonal bisect each other at 90°
• Perimeter = 4a , here a = side of Rhombus .

Given =>

Length of d1 = 16 cm

Length of d2 = 30 cm

Solution =>

As digonal bisect each other then half of both digonals will be -

$\frac{d1}{2}$ = $\frac{16}{2}$ = 8

$\frac{d2}{2}$ = $\frac{30}{2}$ = 15

Now we have to find out the side of Rhombus -

As side = $\sqrt{({8}^{2})({15}^{2})}$

Side. = 17cm

Perimeter = 4a

Perimeter = 4×17

Perimeter = 68 cm

Answer 2

Answer:

68

solution showed above figure