Question

The lengths of the diagonals of a rhombus are 16cm and 12cm. Then,the length of the side of the rhombus is
(a) 9cm (b) 10cm (c) 8cm (d) 20cm

Answer 1

Answer:

a=v (di/2)^2+(d2/2)^2 =

side of Rhombus=v8 ^2+6^

=v100 = 10cm. Ans

Answer 2

$\bf{Hello}$

We know that, the diagonals of a rhombus are perpendicular bisector of each other.Given,  AC = 16 cm and BD = 12 cm       [let]∴ AO = 8cm, SO = 6cm

We know that, the diagonals of a rhombus are perpendicular bisector of each other.Given,  AC = 16 cm and BD = 12 cm        [let]∴ AO = 8cm, SO = 6cmand  ∠AOB = 90°

We know that, the diagonals of a rhombus are perpendicular bisector of each other.Given,  AC = 16 cm and BD = 12 cm        [let]∴ AO = 8cm, SO = 6cmand  ∠AOB = 90°In right angled ∠AOB,

8×8,6×6 = 64+36=100

Ab = 10 cm

$\boxed{HOPE IT HELPS YOU}$