Question

the Lengths of the diagonals of a rhombus are 16cm and 12cm. Find the length of the side of the rhombus .

Answer it ! ​

Answer 1

Answer:

a=10cm

p Diagonal

16

cm

q Diagonal

12

Answer 2

Answer:

10 cm

Step-by-step explanation:

let the rhombus be ABCD with diagonals as AC and BD.

Let the diagonals intersect each other at point O.

We know that,

Diagonals of a Rhombus bisect each other.

So,

OA = OC = 8 cm

OB = OD = 6 cm

Now we have four minor triangles in the rhomus, i.e., OAB, OBC, OCD and OAD.

Applying Pythagoras Theorem in any of the triangle say OAB,

$\sf AB^2=OA^2+OB^2\\\sf AB^2=8^2+6^2\: cm^2\\\sf AB = \sqrt{100\: cm^2}\\\sf AB = 10 cm$

Since, rhomus has all the four sides equal.

Therefore, we have:

AB = BC = CD = AD = 10 cm

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