The lengths of the diagonals of a rhombus are 18cm and 24cm. What is it the distance between the parallel sides?
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D1=18cm
D2=24cm
now we know that the diagonals of a rhombus bisect each other at right angles...
therefore....let they bisect at point O
therefore....For ∆AOB
AO=24/2=12cm
OB=18/2cm=9cm
therefore...the side of the Rhombus..
√(9²+12²)=√225=15cm
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