Math, asked by diyapriyananda, 16 days ago

The lengths of the diagonals of a rhombus are 24cm and 32cm, then the length of the

altitude of the rhombus is

(a) 12cm (b) 12.8cm (c) 19 cm (d) 19.2cm​

Answers

Answered by MayankMandavkar
1

Answer:

d) 19.2

Step-by-step explanation:

Area of the Rhombus

= 1/2 d1 d2 =1/2 ×240× 32 = 384 cm^2

Using Pythagoras theorem

side ^2 = (1/2 d1)^2 + (1/2 d2)^2 = 12^2 16^2 = 144 + 256 = 400

Side = 20cm

Area of the Rhombus = base × altitude

384 = 20 × altitude

So altitude = 384/20 = 19.2 cm

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