the lengths of the diagonals of a rhombus are 26 cm and 16 cm respectively find the length of each side of the Rhombus
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Answer:
□ABCD is a Rhombus
AC = 26 cm
BD = 16 cm
Point O is meeting point of diagonals
AO = 1/2 AC
( DIAGONAL OF A RHOMBUS ARE PERPENDICULAR BISECTOR OF EACH OTHER )
AO = 1/2 × 26 = 13 CM
BO = 1/2 BD
( DIAGONAL OF A RHOMBUS ARE PERPENDICULAR BISECTOR OF EACH OTHER )
BO = 1/2 × 16 = 8 cm
Now You can find the side using Pythagoras Theorem
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