Question

the lengths of the diognals of a rhombus are 16 c.m.and 12 c.m. respectiverly find the length of each of its sides​

Answer 1

Step-by-step explanation:

given,

diagonals of a rhombus are 16cm and 12 cm

area of the rhombus=1/2 ×d1×d2

=1/2×16×12

=96cm^2

therefore,

the length of each of it's sides are 96cm

Answer 2

Step-by-step explanation:

let the rhombus be ABCD

let the diagonal bisect each other at O

In triangle AOB,

AO= 16/2 cm = 8 cm

BO=12/2 cm =6 cm

We know that the diagonals bisect each other at 90 degrees

:AB is the hypotenuse

By Pythagoras theorem,

(AB)^2 = (AO)^2 + (BO)^2

(AB)^2 =(8)^2 + (6)^2

= 64 + 36

= 100

AB =

$\sqrt{100} = 10 \: cm$