Question

The lengths of the shorter and longer parallel sides of a trapezium are a and b cm respectively. If the area of the trapezium is 4 ( a^2 - b^2 ) , then the height of the trapezium is

guys please tell me the height of trapezium and the correct answer is 8 ( a - b) , please don't scam or i will report you. Please tell its answer it is urgent. ​

Answer 1

Answer:

Area of trapezium =

2

1

× Sum of parallel sides × height

⇒

2

1

×(x+y)× height =(x

2

−y

2

)

⇒ height =

(x+y)

2(x+y)(x−y)

=2(x−y

Answer 2

answer :-

area of trapezium :- 1/2 × sum of parellal side × height

$\frac{1}{2} \times (a + b) \times h = 4(a {}^{2} - b {}^{2})$

$h = \frac{8(a + b)(a - b)}{(a + b)}$

$h = 8(a - b)$

so, height is 8 (a - b)

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