Math, asked by krishinfo20, 8 months ago

The lengths of the sides of a quadrilateral are
in the ratio 1:2:3:4 of the sum of all
sides is 5o cm, find all the four sides.

any plz solve fast​

Answers

Answered by Brainlyunknowngirl
50

Correct Question :

The lengths of the sides of a quadrilateral are in the ratio 1:2:3:4 of the sum of all sides is 50 cm, find all the four sides.

Answer:

The sides of the quadrilateral are 5 cm, 10 cm, 15 cm and 20 cm.

Step-by-step explanation:

Given,

  • The perimeter = 50 cm.

To find,

  • All the sides of the quadrilateral.

Let x , 2x, 3x, & 4x be the length of the sides of the quadrilateral.

Now,

x + 2x + 3x + 4x = 50

➝ 10x = 50

➝ x = 50/10

➝ x = 5

.°. x = 5

Finding all the sides :

x = 1 × 5 → 5

2x = 2 × 5 → 10

3x = 3 × 5 → 15

4x = 4 × 5 → 20

Hence, the sides of the quadrilateral are 5 cm, 10 cm, 15 cm and 20 cm.


ItzArchimedes: Awesome !
Answered by OfficialPk
76

\mathcal{Given \: Perimeter \: = \: 50 \: cm}

\underline\mathsf\green{perimeter} = \mathsf{Sum \: of \: all \: sides \: of \: polynomial}

\mathcal{Let \: sides \: be \: 1x , 2x , 3x , \: and \: 4x}

\mathcal{1x+2x+3x+4x \: = \: 50}

\mathcal{10 x \: = \: 50}

\mathcal{x \: = \: \frac{50}{10}}

\mathcal{\therefore x \: = \: 5}

\underline\mathsf\orange{Four \: sides \: are}

1x = 5 \times 1 = 5 \\ 2x = 2 \times 5 = 10 \\ 3x = 3 \times 5 = 15 \\ 4x = 4 \times 5 = 20

\huge\mathit\red{Mark \: me \: as \: brainlist}

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