Question

The lengths of the sides of a triangle are in ratio 15:12:13 and it's perimeter is 200m. Find the area of the triangle.​

Answer 1

Answer:

Let the sides of the triangle be 13a,14a,15a.

Perimeter of the triangle = Sum of all sides =13a+14a+15a=42a

Given, perimeter of the triangle =84cm

∴42a=84cm

a=2cm

So, the sides of the triangle are 13a=26cm,14a=28cm,15a=30cm.

Area of triangle with sides a, b, and c and s=

2

a+b+c is s(s−a)(s−b)(s−c)

For triangle with sides 26 cm, 28 cm and 30 cm, s= 226+28+30

=42cm

Area of the triangle with 26 cm, 28 cm and 30 cm = 42(42−26)(42−28)(42−30)

= 42×16×14×12= 6×7×4×4×7×2×6×2=6×7×4×2=336cm 2

Step-by-step explanation:

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Answer 2

Answer:Triangle's ratio=15:12:13

we know that

sum of sides of triangle = perimeter

15x+12x+13x=200m

x=5

Sides of triangle=15x=75

12x=60

13x=65

s=75+60+65/2

=100

area=by using heron's formula=√100(100-60)(100-65)(100-75)=1871 m square