The lengths of the sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 144 cm. Find the area of the triangle .
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Given, Side of triangle are in ratio 3:4:5 and their perimeter 144 cm.
Let the sides of triangle be 3x,4x,5x
Perimeter =3x+4x+5x=144 cm
12x=144
∴x=12
Then sides of triangle are 3x=3×12=36 cm,
4x=4×12=48 cm,
5x=5×12=60 cm.
Now, Semi perimeter, s=
2
Sum of sides of triangle
=
2
36+48+60
=72 cm
Using Heron's formula, Area of triangle =
s(s−a)(s−b)(s−c)
=
72(72−36)(72−48)(72−60)
=
72×36×24×12
=864 cm
2
Let the sides of triangle be 3x,4x,5x
Perimeter =3x+4x+5x=144 cm
12x=144
∴x=12
Then sides of triangle are 3x=3×12=36 cm,
4x=4×12=48 cm,
5x=5×12=60 cm.
Now, Semi perimeter, s=
2
Sum of sides of triangle
=
2
36+48+60
=72 cm
Using Heron's formula, Area of triangle =
s(s−a)(s−b)(s−c)
=
72(72−36)(72−48)(72−60)
=
72×36×24×12
=864 cm
2
Answered by
0
Answer:
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