Question

The lengths of the sides of a triangle are in the ratio 3:4:5 and its
perimeter is 168 m. Find its sides.

Answer 1

Explanation:

Given :-

The lengths of the sides of a triangle are in the ratio 3:4:5 and its perimeter is 168 m.

To find :-

Find its sides ?

Solution :-

Given that

The lengths of the sides of a triangle are in the ratio 3:4:5

Let they be 3X m , 4X m and 5X m

We know that

Perimeter of a triangle = Sum of all the three sides

=> Perimeter = 3X+4X+5X m

=> Perimeter = 12X m

According to the given problem

Perimeter of the given triangle = 168 m.

=> 12X = 168

=> X = 168/12

=> X = 14 m

Now,

If X = 14 m then 3X = 3(14) = 42 m

If X = 14 m then 4X = 4(14) = 56 m

If X = 14 m then 5X = 5(14) = 70 m

The sides are 42 m , 56 m and 70 m

Answer:-

The three sides of the given triangle are 42 m , 56 m and 70 m

Check:-

The three sides = 42 m , 56 m and 70 m

Perimeter = 42 + 56 + 70 = 168 m

Verified the given relations in the given problem.

Used formulae:-

→Perimeter of a triangle = Sum of all the three sides

→ If a, b, c are the three sides of a triangle then the perimeter is (a+b+c) units .