The lengths of the sides of a triangle are integers,and its area is also integger.one side is 21 and the perimeter is 48.find the shortest side
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Let the other sides be x or x
perimeter of triangle = sum of all sides
48= x+x+21
48 = 21+2x
48 - 21 = 2x
27 = 2x
27÷ 2= x
13.5= x
the shortest side is 13.5
Check answer = 13.5+13.5+21= 48.0
So it is prove
perimeter of triangle = sum of all sides
48= x+x+21
48 = 21+2x
48 - 21 = 2x
27 = 2x
27÷ 2= x
13.5= x
the shortest side is 13.5
Check answer = 13.5+13.5+21= 48.0
So it is prove
lenghts of sides are integers but your side lenght is 13.5 which is not integer
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