Question

the lengths of the sides of a triangle are y ,y +8 ,10 .the perimeter is 56. .what is the value of y​

Answer 1

Answer:

y+y+8+10=56

2y+18 =56

2y=56-18

2y=38

y=38/2

y=19

Answer 2

Given : The lengths of the sides of a triangle are y , y +8 & 10 .

Need To Find : The Value of y .

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❒ Let's consider A , B & C be the three sides of Triangle.

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{Perimeter _{(Triangle)} \:: A + B + C }\bigg\rgroup$

⠀⠀⠀⠀Here A , B & C are three sides of Triangle & we know that Perimeter of Triangle is 56 cm .

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \longmapsto \sf 56 = y + y + 8 + 10$

$\qquad \longmapsto \sf 56 = y + y + 18$

$\qquad \longmapsto \sf 56 - 18 = y + y$

$\qquad \longmapsto \sf 38 = y + y$

$\qquad \longmapsto \sf 38 = 2y$

$\qquad \longmapsto \sf y = \cancel {\dfrac{38}{2}}$

$\qquad \longmapsto \frak{\underline{\purple{\:y = 19 }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:The \:Value \:of\:y \:is\:\bf{19\:}}}}$

⠀⠀⠀⠀&

• First Side of Triangle is y = 19
• Second Side of triangle is (y + 8 ) = 19 + 8 = 27
• Third Side of Triangle is 10

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Three\:Sides \:of\:Triangle \:are\:\bf{19,\:27\:\&\:10\:}}}}$

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