The lengths of the two altitudes of a paralleogram is 4cm ,6 cm perimeter is 40 cm find the length of the sides of paralleogram
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he sides are 2 parallel sides of 8 cm length and 2 parallel sides of 12 cm length.
step by step Explanation:
Assume that the parallelogram is formed by two vectors, →a, and →b.
Given:
p=2∣∣→a∣∣+2∣∣∣→b∣∣∣=40 cm [1]
The height where →b is chosen to be the base
ha=∣∣→a∣∣sin(θ)=4 cm [2]
where θ is the acute angle between →a and →b
The property, adjacent angles of a parallelogram are supplementary, causes the equation for the height when →a is chosen to be the base to become:
hb=∣∣∣→b∣∣∣sin(π−θ)=6 cm [3]
You can use the identity sin(A−B)=sin(A)cos(B)−cos(A)sin(B) to prove that sin(π−θ)=sin(θ):
hb=∣∣∣→b∣∣∣sin(θ)=6 cm [3.1]
Divide equation [2] by equation [3.1]:
∣∣→a∣∣
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