Question

The lengths of the two diagonals of a rhombus are 6cm and 8cm respectively. What is the length of its side?​

Answer 1

Step-by-step explanation:

The Diagonals of rhombus is 6,8cm

The area of rhombus is given as

2

1

×6×8

Thus required area of rhombus is 24 cm

2

The diagonals of the rhombus bisect each other at right angles

So the sides of right triangle formed by diagonals and sides are 3,4

So by pythagoras theorem

Side^2=3^2+4^2

side2=16+9

side =√25

Side=5

Hence length of side is 5 cm

Answer 2

Answer:

The Diagonals of rhombus is 6,8cm

The area of rhombus is given as

$\frac{1}{2} \: \times 6 \: \times 8$

Thus required area of rhombus is 24 cm

$24 \: {cm}^{2}$

The diagonals of the rhombus bisect

each other at right angles.

So the sides of right triangle formed

by diagonals and sides are 3,4

So by pythagoras theorem

${side}^{2} \: = {3}^{2} \: + {4}^{2}$

${side}^{2} = 16 \: + 9$

${side}^{2} = 25$

${side}^{2} = \sqrt{25}$

$side \: = 5$

$hence \: length \: of\: side \: is \: = 5cm$

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