Question

the lengths of two diagonal of a rhombus are 8cm and 6cm .the perimeter of the rhombus is .​

Answer 1

Answer:

8²+6²=x²

64+36=x²

100=x²

x=10

Answer 2

diagonal d1 = 8 = 8/2=4 CM

diagonal d2 =6 = 6/2=3 CM

By phythagoras theorem

4^2+3^2=s^2

16+9

25 = S^2

S= 5 cm

perimeter = 4*s

= 4*5

= 20 cm