Question

The lengths of two parallel chords of a circle
are 8 cm and 14 cm. If the smaller chord is at a
distance of 2 cm from the centre, then what is the
distance of the other chord from the centre

Answer 1

Answer:

this is the answer hope it helps

Step-by-step explanation:

please mark as Brainliest

Answer 2

Let, AB and CD be two parallel chords of a circle with centre O such that AB = 6cm and

CD = 8cm. Draw OM perpendicular AB and ON perpendicular CD.

As AB ||CD and OM perpendicular AB, ON perpendicular CD. Therefore,

Points O, N and M are collinear.

As the perpendicular from the centre of a circle to the chord bisects the chord.

Therefore,

AM = 1/2AB = ½ x6 = 3cm

CN = 1/2CD = 1/2x8 = 4cm

In right triangle OAM, we have

OA2 = OM2 + AM2

OA2 = 42 + 32 ⇒ OA2 =25 ⇒ OA = 5cm

Also, OA = OC (Radii of the same circle)

⇒ OC = 5cm

In right triangle OCN, we have

OC2 = ON2 + CN2

⇒ 52 = ON2 + 42 ⇒ ON2 = 52 – 42

⇒ ON2 = 9 ⇒ ON = 3cm

Answer 3

Let, AB and CD be two parallel chords of a circle with centre O such that AB = 6cm and

CD = 8cm. Draw OM perpendicular AB and ON perpendicular CD.

As AB ||CD and OM perpendicular AB, ON perpendicular CD. Therefore,

Points O, N and M are collinear.

As the perpendicular from the centre of a circle to the chord bisects the chord.

Therefore,

AM = 1/2AB = ½ x6 = 3cm

CN = 1/2CD = 1/2x8 = 4cm

In right triangle OAM, we have

OA2 = OM2 + AM2

OA2 = 42 + 32 ⇒ OA2 =25 ⇒ OA = 5cm

Also, OA = OC (Radii of the same circle)

⇒ OC = 5cm

In right triangle OCN, we have

OC2 = ON2 + CN2

⇒ 52 = ON2 + 42 ⇒ ON2 = 52 – 42

⇒ ON2 = 9 ⇒ ON = 3cm