Math, asked by siallen9380, 1 year ago

The lengths of two parallel sides of a trapezium are 21 cm and 9 cm. If its height is 10 cm, then what is the area (in cm2) of the trapezium

Answers

Answered by mannraj36
1

area of trapezium =1/2 ×h×sum of parallel sides

=1/2×10×(21+9)

=5×30square cm.

=150square cm.

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
3

\huge\sf\pink{Answer}

☞ Area = 150 cm²

\rule{110}1

\huge\sf\blue{Given}

✭ Length of parallel sides of trapezium are 21 cm and 9 cm.

✭ Height(h) of the trapezium is 10 cm

\rule{110}1

\huge\sf\gray{To \:Find}

◈ Area of the trapezius?

\rule{110}1

\huge\sf\purple{Steps}

Area of a Trapezium is given by,

\underline{\boxed{\sf Area = \dfrac{1}{2} \times (Sum \: of \: parallel \: sides) \times height}}

\bullet\underline{\textsf{As Per the Question}}

Substituting the given values,

\sf{\dashrightarrow Area = \dfrac{1}{2} \times (21 + 9) \times 10}

\sf{\dashrightarrow Area = \dfrac{1}{2} \times 30 \times 10}

\sf{\dashrightarrow Area = 15 \times 10}

\sf{\orange{\dashrightarrow Area = 150 \: cm^2}}

\rule{170}3

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