Question

the lenth if mintute hand of clock is 14cm . the area swept by the minute hand in one minute

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Answer 1

Answer:

Given,

Length of the minute hand =14 so, r =14

Step-by-step explanation:

1. In 60 min, it sweeps 360° , so in 1 min, it sweeps 360°/60°= 6°!!
2. Area swept by it in 1 min= 6°/360° × πr²
3. = 22/7× 14× 14 = 60° = =44 × 14 / 60° = 10.26 cm²

• Formula used:-
• Area of sector = theta/360° × πr²

Answer 2

Answer:

Solution. Angle described by the minute hand

in 60 minutes = 360°

Angle described by the minute hand

in 1 minute = (360/60×1)°

= 6°

therefore, ∅ = 6° and radius = 14cm

Area swept by the minute hand in

one minute = (πr2∅/360)

=(22×14×14×6/7×360)cm2

= 10.266 cm2