the lenth of a rectangle is 6 m less than three times its breath find the dimensions of the rectangle , if its perimeter is 148m
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Define x:
Let the breadth be x
Length = 3x - 6
Solve x:
Given that perimeter is 148 m
Perimeter = 2 (Length + Breadth)
2( x + 3x - 6) = 148
2(4x - 6) = 148
8x - 12 = 148
8x = 160
x = 20
Find the dimensions:
Breadth = x = 20 m
Length = 3x - 6 = 3(20) - 6 = 54 m
Answer: The length is 54 m and the breadth is 20 m
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Hey there!
Let the breadth of the rectangle = x.
So, According to the question, Length = 3x - 6 .
Perimeter = 2 ( Length + Breadth)
= 2 ( 3x - 6 + x )
= 2 ( 4x - 6 )
= 8x - 12
According to the question,
Perimeter = 148 m.
Therefore, 8x - 12= 148
. 8x = 148+ 12
8x = 160
x = 20
Hence, Length = 3x-6 = 60 - 6 = 54 m
and Breadth = 20m
Therefore , The required dimensions of the Rectangle are 54 * 20 m.
Let the breadth of the rectangle = x.
So, According to the question, Length = 3x - 6 .
Perimeter = 2 ( Length + Breadth)
= 2 ( 3x - 6 + x )
= 2 ( 4x - 6 )
= 8x - 12
According to the question,
Perimeter = 148 m.
Therefore, 8x - 12= 148
. 8x = 148+ 12
8x = 160
x = 20
Hence, Length = 3x-6 = 60 - 6 = 54 m
and Breadth = 20m
Therefore , The required dimensions of the Rectangle are 54 * 20 m.
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