.The lenth of a rectangle is 8m less tgan thrice its width. If area of the rectangle is 1675sqm then find the length and width of the rectangle....
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rectangle area- lb
3(b-8)=l
1675=b*(3b-24)
3b²-24b-1675
please solve equation yourself
3(b-8)=l
1675=b*(3b-24)
3b²-24b-1675
please solve equation yourself
sukhi132259:
hi
Answered by
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Answer: length=67m & width is 25m
Step-by-step explanation:
Let the width of rectangle be b then,
l=3b-8. (By questions)
Therefore,area of rectangle is l×b
=( 3b-8)×b
=(3b^2-8b)
By question,
(3b^2-8b)=1675
or,3b^2-8b-1675=0
or,3b^2-75b+67b-1675=0
or,3b(b-25)+67(b-25)=0
or,(b-25)(3b+67)=0
or, b=25. Or b=-67/3
Since distance could not be negative or in fraction.
So the width of rectangle is 25m
And length is 3×25-8=75-8=67m
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