Question

the lenth of a rectangular filed is 8m less than twice breadth . if the perimeter of rectangular filed is 56 meters, find is length and breadth?​

Answer 1

$\huge\mathcal{\fcolorbox{red}{black}{\green{ᴀɴsᴡᴇʀ࿐}}}$

Solution:-

Let the breadth of the rectangular field be 'x' .

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

According to the question:-

✯ The length of the rectangular field is 8 meter less than twice the breadth.

Hence,

$✯ \large{\bf\pink{2x - 8}}2x−8$

.

$\pink{\bigstar}★ \large\underline{\boxed{\bf\green{Perimeter_{(rectangle)} = 2(l + b)}}}$

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• • Substituting in the Formula:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf 56 = 2(2x - 8 + x)56=2(2x−8+x)$

⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf 56 = 2(3x - 8)56=2(3x−8)$

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$\sf 56 = 6x - 1656=6x−16$

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$\sf 6x = 56 + 166x=56+16$

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$\sf 6x = 726x=72$

$➪ \sf x = \dfrac{72}{6}$

$★ \large{\underline{\underline{\bf\red{ x = 12 \: m}}}}\dashrightarrow\bf\blue{[Breadth]}$

Answer 2

Answer:

$\huge\mathcal{\fcolorbox{red}{black}{\green{ᴀɴsᴡᴇʀ࿐}}}$

Solution:-

Let the breadth of the rectangular field be 'x' .

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

According to the question:-

✯ The length of the rectangular field is 8 meter less than twice the breadth.

Hence,

$✯ \large{\bf\pink{2x - 8}}2x−8$

.

$\pink{\bigstar}★ \large\underline{\boxed{\bf\green{Perimeter_{(rectangle)} = 2(l + b)}}}$

⠀⠀⠀⠀⠀⠀⠀

• Substituting in the Formula:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf 56 = 2(2x - 8 + x)56=2(2x−8+x)$

⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf 56 = 2(3x - 8)56=2(3x−8)$

⠀⠀⠀⠀⠀⠀⠀

$\sf 56 = 6x - 1656=6x−16$

⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf 6x = 56 + 166x=56+16$

⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf 6x = 726x=72$

$➪ \sf x = \dfrac{72}{6}$

$★ \large{\underline{\underline{\bf\red{ x = 12 \: m}}}}\dashrightarrow\bf\blue{[Breadth]}$