the lenth of diaginal of a rambus are 10 cm and 24 cm. find it's perimeter
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Diagonals of the rhombus 10,24 cm
since the diagonals meet at the center of the rhombus,
they create 4 right angles in the center.
so in this, we can use the Pythagoras theorem, which
states that the sum of squares on the height and
the base of a right angle is equal is square on the
hypotenuse.
Length of the base =
2
10
=5 cm
Length of the height =
2
24
=12 cm.
By Pythagoras theorem,
Hypotenuse=(5)
2
+(12)
2
(AB)
2
=25+144
(AB)
2
=169
2
=AB=
(13)
2
∴ Hypotenuse =13 cm
So, the side of a rhombus is 13 cm.
the perimeter of the rhombus =4×side
=4×13
=52 cm
Therefore, the perimeter of the rhombus is 52 cm.
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