the lenth of diaginal of a rambus are 10 cm and 24 cm. find it's perimeter
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The length of diagonals of a rhombus are 10 cm and 24 cm. Find it's perimeter.
Diagonals meet at the centre and forms right-angled triangles.
So by using pythagoras theorem
Length of the base = 10/2 = 5cm
Length of the height = 24/2 = 12cm
Hypotenuse^2 = side ^+ side^2
Hypotenuse^2= 52+ 122
Hypotenuse^2 = 25 + 144
Hypotenuse^2 = 169
On taking square root we get,
Hypotenuse = 13 { 13 X 13=169 => √169=13}
Hence the side of the rhombus is 13cm.
Perimeter of the rhombus = 4×side
= 4 × 13
= 52cm.
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use string theory and tear your copy
Explanation:
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