the lenth of rectangular field is 8m less than twice its breadth if the perimeter of the rectangular field is 56m find its length and breadth
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Answered by
6
length=2x-8
breadth =x
p=56m
56=2(2x-8+x)
56=2(3x-8)
56=6x-16
56+16=6x
72=6x
72/6=x
x=12
breadth =x
p=56m
56=2(2x-8+x)
56=2(3x-8)
56=6x-16
56+16=6x
72=6x
72/6=x
x=12
Answered by
6
Let the breadth be x
⇒length =2x-8
Perimeter of a rectangle = 2(l+b)
⇒2(2x-8+x)=56m
⇒6x-816=56m
⇒6x=56+16=72
⇒x=72/6=12
∴x=12
⇒length=2x-8
=2(12)-8=16
Breadth=x=12
⇒length =2x-8
Perimeter of a rectangle = 2(l+b)
⇒2(2x-8+x)=56m
⇒6x-816=56m
⇒6x=56+16=72
⇒x=72/6=12
∴x=12
⇒length=2x-8
=2(12)-8=16
Breadth=x=12
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