Question

The lents and the breadth of a rectangular piece of land are 500 m and 300 m
3. Find the breadth of a rectangular plot of land, if its area is 440 m and length is
EXERCISE 11.1
respectively. Find
(1) its area () the cost of the land, if I m of the land costs? 10.000
2. Find the area of a square park whose perimeter is 320 m.
3
6
so
22 m. Also find its perimeter.
4, The perimeter of a rectangular sheet is 100 cm. If the length is 35 cm, find its breadth
Also find the area,
5/ The area of a square park is the same as of a rectangular park. If the side of the
square park is 60 m and the length of the rectangular park is 90 m, find the breadth di
the rectangular park
A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. 1 dhe
same wire is rebent in the shape of a square, what will be the measure of each side
Also find which shape encloses more area?
( a
The perimeter of a rectangle is 130 cm. If the breadth of the rectangleis
30 cm, find its length. Also find the area of the rectangle.
X. A door of length 2 m and breadth Imis fiued in a wall. The length of the
wall is 4.5 m and the breadth is 3.6 m (Fig11.6). Find the cost of white
washing the wall, if the rate of white washing the wall is é 20 per m
11.6

Answer 1

Given: Length of a rectangular piece of land =500m

and Breadth of a rectangular piece of land =300 m

Area of a rectangular piece of land = Length × Breadth =500×300=1,50,000m

2

Since, the cost of 1m

2

land = Rs 10,000

∴, the cost of 1,50,000m

2

land =10,000×1,50,000=Rs1,50,00,00,000

Answer 2

Answer:

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Step-by-step explanation:

1 ) Given: l = 500 m, b = 300 m

(i) Area = l × b

= 500 m × 300 m = 150000 m square

(ii) Cost of land = ₹ 10,000 × 150000 = ₹ 15,00,000,000

2 ) Given: Perimeter = 320 m

Side of the square =  Perimeter 4

=3204 m=80 m

Area of the square = Side × Side

= 80 m × 80 m = 6400 m square

3 )Given: Area = 440 m2

Length = 22 m

Breadth =  Area / Length =440 m square / 22 m

=20 m

Perimeter = 2[l + b] = 2 [22 m + 20 m]

= 2 × 42 m = 84 m

4 ) Given: Perimeter = 100 cm

Length = 35 cm

Perimeter = 2(l + b)

100 = 2(35 + b)

100 / 2=35+b

⇒ 50 = 35 + b

⇒ b = 50 – 35 = 15 cm

∴ Breadth = 15 cm

Area = l × b = 35 cm × 15 cm

= 525 cm square