the letter of word SOCIETY are placed at a random in a row . what is the probability that three vowels come together.
don't give useless answers, if you don't know.
Answers
Answered by
14
Answer:
Step-by-step explanation:
3 vowels in ‘society’ : { ‘o’, ‘i’, ‘e’ }
rest of the words ( 7 - 3 ) = 4
No of ways 3 vowels can be rearranged: 3! = 3 * 2 = 6
No of ways {rest of the words} can be rearranged: 4! = 4 * 3 *2 = 24
If we assume all the 3 vowels = { a single character }, we will have in total 5 different characters which by similar principle can be rearranged in 5! ways.
Since the { single character can actually be rearranged in 3! ways } the no. of ways we have is 5! * 3! ways = 120 * 6 = 720
hharasudhan539:
mark as Brainlest answer
then figure it out by ourself
both answers are wrong
However, this answer given by hharasudhan isn't wrong, its just that its incomplete
Answered by
18
probability = all vowels together/ total number of permutations
If all vowels are together
(OIE) + S C T Y ( consider OIE as one alphabet)
1 + 4 = 5! arrangements
Total arrangements possible = 7!
Answer = 5!/7!
= 1/7 x 6
= 1/42
If all vowels are together
(OIE) + S C T Y ( consider OIE as one alphabet)
1 + 4 = 5! arrangements
Total arrangements possible = 7!
Answer = 5!/7!
= 1/7 x 6
= 1/42
both your answer are wrong
Is the answer 1/7 ?
yes
numerator will be 5! x 3!
I forgot to do the permutations of OLE
I hope you've got how to do it
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