the letters of the word MUMMY are placed at a random in a row ,the chance that the letters at the extremes are M andY is
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HELLO FRIEND HERE IS YOUR ANSWER,,,,,,
Let us take the total number of obtaining the placement of 5 total letters in a complete row which are having 3 letters as the same
Here permutations and combinations are applied to obtain the answer,,,,
STEP BY STEP SOLUTION::;
Therefore, to find a number of total ways in which "M" is present at the extremes, we can conclude that, the remaining three letters, that is, "M" , "U" , "Y" , can get into the place in between them and in P , that is , in a total of "6 ways" it can be placed.....
FINDING THE TOTAL PROBABILITY,,, we get
Therefore,,, P =
Final answer,,,
P =
Which is the required solution for this type of query.
HOPE IT HELPS YOU AND CLEARS YOUR DOUBTS FOR USING PERMUTATIONS AND COMBINATIONS ALONG WITH PROBABILITY!!!!!
Let us take the total number of obtaining the placement of 5 total letters in a complete row which are having 3 letters as the same
Here permutations and combinations are applied to obtain the answer,,,,
STEP BY STEP SOLUTION::;
Therefore, to find a number of total ways in which "M" is present at the extremes, we can conclude that, the remaining three letters, that is, "M" , "U" , "Y" , can get into the place in between them and in P , that is , in a total of "6 ways" it can be placed.....
FINDING THE TOTAL PROBABILITY,,, we get
Therefore,,, P =
Final answer,,,
P =
Which is the required solution for this type of query.
HOPE IT HELPS YOU AND CLEARS YOUR DOUBTS FOR USING PERMUTATIONS AND COMBINATIONS ALONG WITH PROBABILITY!!!!!
kmadhunaiah:
another question sir. A three digited number is written down at random.the probability that last two identical place values is
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