Question

The letters of the word PRINT are written on similar
Cardboards. These cardboards are then mixed and
put upside down so that no one can see the letters
Reyansh takes one of the said cardboards What is
the probability that it has letters N or k on it ?​

Answer 1

Step-by-step explanation:

The Letters of the word ⇒ SWORD

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)=

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s)

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s)

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s)

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s) P(E)=

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s) P(E)= 5

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s) P(E)= 51

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s) P(E)= 51

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s) P(E)= 51

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)= n(E)n(s) P(E)= 51 Hence, this is the answer