The letters R, M, O represent whole numbers .If R×M×O =240, R×O+M=46 and R+M×O=64 find R, M, O
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Let, R = x ; M = y ; O = z
xyz = 240.......(1)
xz + y = 46.......(2)
x + yz = 64......(3)
From (1) :-
yz = 240/x......(4)
Now, put the value of yz in (3) from (4)
x + 240/x = 64
(x² + 240)/x = 64
x² + 240 = 64x
x² - 64x + 240 = 0
Value of x = 8.......(5)
Now, keep the value of (5) obtained in (4)
yz = 240/x
yz = 240/8
yz = 30
y = 30/z.......(6)
Put the value of (6) in (2)
xz + y = 46
8z + 30/z = 46
(8z² + 30)/z = 46
8z² + 30 = 46z
8z² - 46z + 30 = 0.......(7)
Divide the equation (7) with 2
4z² - 23z + 15 = 0
z = 10
So, R = 8 ; O = 10 and M = 3
Hope it helps !
#Shati
#Brainly benefactor
xyz = 240.......(1)
xz + y = 46.......(2)
x + yz = 64......(3)
From (1) :-
yz = 240/x......(4)
Now, put the value of yz in (3) from (4)
x + 240/x = 64
(x² + 240)/x = 64
x² + 240 = 64x
x² - 64x + 240 = 0
Value of x = 8.......(5)
Now, keep the value of (5) obtained in (4)
yz = 240/x
yz = 240/8
yz = 30
y = 30/z.......(6)
Put the value of (6) in (2)
xz + y = 46
8z + 30/z = 46
(8z² + 30)/z = 46
8z² + 30 = 46z
8z² - 46z + 30 = 0.......(7)
Divide the equation (7) with 2
4z² - 23z + 15 = 0
z = 10
So, R = 8 ; O = 10 and M = 3
Hope it helps !
#Shati
#Brainly benefactor
anubhav100:
u have made it wrong
Answered by
0
Let, R = x ; M = y ; O = z
xyz = 240.......(1)
xz + y = 46.......(2)
x + yz = 64......(3)
From (1) :-
yz = 240/x......(4)
Now, put the value of yz in (3) from (4)
x + 240/x = 64
(x² + 240)/x = 64
x² + 240 = 64x
x² - 64x + 240 = 0
Value of x = 8.......(5)
Now, keep the value of (5) obtained in (4)
yz = 240/x
yz = 240/8
yz = 30
y = 30/z.......(6)
Put the value of (6) in (2)
xz + y = 46
8z + 30/z = 46
(8z² + 30)/z = 46
8z² + 30 = 46z
8z² - 46z + 30 = 0.......(7)
Divide the equation (7) with 2
4z² - 23z + 15 = 0
z = 10
So, R = 8 ; O = 10 and M = 3
Hope it helps !
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