The level of blood in a bottle used to give blood to a patient is 1.3 metre high above the needle which is 3 cm in length and has an internal diameter of 0.36 if 4.5 cm cube of blood is passing through the needle per minute calculate the viscosity of blood the density of blood 10 20 kg per metre cube ignore fallen level of blood in the bottle
Answers
Answer:
Explanation:
=> Flow rate to pressure difference:
∅ = πr⁴|ΔP| / 8ηL
where,
∅ = rate of flow = 4.5cm³/min=7.5×10⁻⁸m/sec
ΔP = pressure difference between two ends = ρgh=1020×9.8×1.3=12994.8 Nm⁻²
L = length of tuber = 3 cm = 0.03 m
r = 0.36/2 mm = 0.18 * 10⁻³ m
η = viscosity = ?
=> For viscosity we have,
η = πr⁴|ΔP| / 8L∅
= 3.14 * (0.18 * 10⁻³)⁴ * 12994.8 / 8 * 0.03 * 7.5 * 10⁻⁸
= 2.38 * 10⁻³ N. s. m⁻²
Thus, the viscosity of the blood is 2.38 * 10⁻³ N. s. m⁻².
Answer:Flow rate to pressure difference:
∅ = πr⁴|ΔP| / 8ηL
where,
∅ = rate of flow = 4.5cm³/min=7.5×10⁻⁸m/sec
ΔP = pressure difference between two ends = ρgh=1020×9.8×1.3=12994.8 Nm⁻²
L = length of tuber = 3 cm = 0.03 m
r = 0.36/2 mm = 0.18 × 10⁻³ m
η = viscosity = ?
=> For viscosity we have,
η = πr⁴|ΔP| / 8L∅
= 3.14 × (0.18 × 10⁻³)⁴ × 12994.8 / 8 × 0.03 × 7.5 × 10⁻⁸
= 2.38 × 10⁻³ N. s. m⁻²
Thus, the viscosity of the blood is 2.38 × 10⁻³ N. s. m⁻².
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Explanation: