the level of sea at 5 p.m. on a Day was 50 cm. above the normal level. It fell by 10 cm. every day. In how many days will it fall to 20 cm. below the normal level
Answers
Answer:
7 days
Step-by-step explanation:
if 1 day = 10
how many days will it take for the water to drop to normal
50/10 = 5
in 5 days the water will be at the normal level
20/10 =2
in two days it will be 20cm below
hence the total number of days will be 7days
I hope it's beneficial
Answer: It will take 2 days for the sea level to fall to 20 cm below the normal level.
Step-by-step explanation: Find out first how much the sea level decreases daily. We are aware that the sea level initially dropped by 50 cm above normal before continuing to drop daily by 10 cm. Hence, each day's net decline in sea level is 40 cm (50 cm minus 10 cm).
We now need to calculate the number of days it will take for the sea level to drop to 20 cm below its usual level. Let's call this amount of time "d" days.
The starting sea level was 50 cm higher than usual. The sea level must drop by 70 cm (50 cm above normal + 20 cm below normal) in order to get to 20 cm below normal.
Hence, a 70 centimetre drop in sea level is required in total. We can develop an equation to describe the 40 cm that the water level recedes from the surface each day:
40 cm times d = 70 cm
To solve for "d," we obtain:
d = 70 cm / 40 cm
d = 1.75
The sea level will therefore drop to 20 cm below normal after 1.75 days. We must round up to the nearest entire number of days because we are unable to have fractions of a day. Because of this, it will take 2 days for the sea to recede 20 cm below its usual level.
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