Question

The level of water in a storage tank is 1.8m.If the density of water is 1.1g/cm3,determine the pressure at the bottom of the tank.(g=10N/Kg,atmospheric pressure=10500N/M2)

Answer 1

Answer:

3.03 × 10⁴ N / m² .

Explanation:

Given :

Height h = 1.8 m

Density of water = 1.1 g / cc = 1100 kg / m³

Atmospheric pressure P₀ = 10500 N / m²

Pressure at the bottom of the tank P = P₀ + ρ h g

P = 10500 + ( 1100 × 1.8 × 10 ) N / m²

P = 10500 + 19800 N / m²

P = 30300 N / m²

P = 3.03 × 10⁴ N / m² .

Therefore , pressure at the bottom of the tank is 3.03 × 10⁴ N / m²

Answer 2

Answer:

• The pressure at the bottom of the tank is 3.03 × 10⁴ Pascals.

Given:

1. Height of the tank (h) = 1.8 m.
2. Density of water (ρ) = 1.1 g / cm³ = 1100 Kg / m³.
3. Atmospheric pressure (P₀) = 10500 N / m²

Explanation:

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From the formula we know,

⇒ P = P₀ + hρg

Where,

• P is the final Pressure.
• P₀ is the external pressure i.e. Atmospheric Pressure.
• h denotes Height.
• ρ denotes Density.

Now,

⇒ P = P₀ + hρg

Substituting the values,

⇒ P = 10500 + 1.8 × 1100 × 10     ∵[g = 10 m/s²]

⇒ P = 1.05 × 10⁴ + 18 × 1100

⇒ P = 1.05 × 10⁴ + 19800

⇒ P = 1.05 × 10⁴ + 1.98 × 10⁴

⇒ P =  10⁴ ( 1.05 + 1.98 )

⇒ P =  10⁴ × 3.03

⇒ P = 3.03 × 10⁴

⇒ P = 3.03 ×  10⁴ Pascals.

∴ The pressure at the bottom of the tank is 3.03 × 10⁴ Pascals.

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