Chemistry, asked by meholi7698, 1 year ago

The Li²⁺ ion is a hydrogen like ion that can be described by the Bohr model. Calculate the Bohr radius of the third orbit and calculate the energy of an electron in 4th orbit.

Answers

Answered by abhi178
10
According to Bohr's theory ,
Bohr radius of nth orbit is given by rₙ = 0.529 × n²/Z A°
Here n indicates nth orbit where electron revolves around the nucleus.

Here, Z = 3 and n = 3
Bohr radius of 3rd orbit = 0.529 × 3²/3 = 0.529 × 3 A°
= 1.587 A°

energy of electron in nth orbit is given by E = - 13.6 × Z²/n² eV
Energy of electron in 4th orbit = - 13.6 × (3)²/(4)² eV [ for Li²⁺ , Z = 3 ]
= - 13.6 × 9/4 eV
= - 13.6 × 2.25 eV
= -30.6 eV
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