The lid of a rectangular box of side 40centimeter by10centimeter is sealed all around with tape. What is the length of the tape required
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length L = 40cm
breadth B = 10cm
A/c to the question, the lid of the rectangle is sealed with a tape which implies that only the outer circumference of the rectangle is covered by tape. So if we find out the circumference of the rectangle then we can easily imply the value of the length of the required tape,
circumference of the rectangle
= 2(L+B)
= 2(40+10)cm
= 2(50)cm
= 100cm.
Therefore, length of the required tape is 100cm.
breadth B = 10cm
A/c to the question, the lid of the rectangle is sealed with a tape which implies that only the outer circumference of the rectangle is covered by tape. So if we find out the circumference of the rectangle then we can easily imply the value of the length of the required tape,
circumference of the rectangle
= 2(L+B)
= 2(40+10)cm
= 2(50)cm
= 100cm.
Therefore, length of the required tape is 100cm.
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