The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape reauired?
Answers
Answer:
100 cm or 1 m
Step-by-step explanation:
the length of the tape will be equal to the perimeter of the lid.
perimeter of rectangle=2(l+b)
perimeter=2(40+10)
= 2×50
=100 cm
length of tape required=100 cm
=1 m
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✦ Question :-
The lead of a rectangular box of side 40 cm by 20 metre is sealed all round with tape what is the length of the tape word?
Answer :-
Length [l]
Given :
Length of the rectangular box = 40 cm
Breadth of the rectangular box = 10 cm
Find :
Length = ?
Solution :-
According to the Question :-
Length of tape required = Perimeter of the rectangular box
So , Applying formula :-
Perimeter of rectangle = 2 ( l + b )
= 2 (40 + 10)
= 100 cm
Now , Converting it into cm
= 10 m is the required answer .
Additional Notes :-
❥ Perimeter of Rectangle = 2( L + B )
❥ Perimeter of square = 4 × Side
❥ Perimeter of triangle = AB + BC + CA
❥ Area of Rectangle = L × B
❥ Area of Square = ( side ) ²
❥ Area of Rhombus = Product of Diagonal/2.
❥ Area of Parallelogram = Base × Height.
❥ Area of triangle = 1/2 × base × height .