Question

The lid of a rectangular box of sides 40 cm by 10 m is to be sealed all round with tape. What is
the length of the tape required?
​

Answer 1

Answer:

Given :

Length = 40 cm = 40 ÷ 100 = 0.4m

Breadth = 10 m

To Find :

Length of tape required

Solution :

Perimeter = 2 × ( l + b )

= 2 × 0.4 + 10

= 2 × 10.4

= 20.8 m

So 20.8m length of tape is required

Answer 2

☆ Solution ☆

Given :-

• The lid of a rectangular box of sides 40 cm by 10 m is to be sealed all round with tape.

To Find :-

• What is the length of the tape required ?

Step-by-Step-Explaination :-

Length of the tape = Perimeter of rectangle

So,

As we know that :-

Perimeter of rectangle = 2 ( l + b )

Where,

length = 40 cm

Breadth = 10 m

Putting the respective value,

Perimeter of rectangle = 2 ( 40 + 10 )

Perimeter of rectangle = 2 × 50

Perimeter of rectangle = 100 cm

Now,

100 cm = 100/100 = 1 m

Hence,

The length of the tape required = 100 cm or 1 m