Question

The lid of a rectangular box of sides 40cm by 10cm is sealed all around with tape . What is the length of the tape required ?​

Answer 1

$\huge\mathcal{{\colorbox{navy}{{\colorbox{lightblue}{Answer}}}}}$

Total length of tape required = Perimeter of Rectangle

= 2 ( length + breadth )

= 2 ( 40 + 10 )

= 2 * 50

= 100cm

= 1m

Answer 2

Qᴜᴇsᴛɪᴏɴ:-

The lid of a rectangular box of sides 40cm by 10cm is sealed all around with tape . What is the length of the tape required ?

Aɴsᴡᴇʀ:-

Length of the tape required is 1 m.

Explanation:-

Given, Sides of box is 40cm and 10cm

So, length of the tape required is = perimeter of the rectangle

$\text { Perimeter of rectangle } \sf=2(l+b)$

$\bf=2 \times(40+10) \mathrm{cm}=2×(40+10)cm$

$\bf=2 \times 50 \mathrm{cm}=2×50cm$

$\bf= 100 cm$

$\bf= 1 m$

$\mapsto\small\bold\pink{The \: length \: of \: the \: required \: tape \: 1 m}$