The lid of a rectangular box of sides 45 cm and 15 cm is sealed all around with tape . What is the length of tape required?
Answers
The length of the tape is 118 cm
Step-by-step explanation:
[ In order to solve this problem, we have to understand that when a shape is sealed all around with a tape, the perimeter of the figure is covered, which happens in this problem. ]
Given that, the sides of the rectangular box are 45 cm and 14 cm.
Then the perimeter of the lid of the rectangular box is
= 2 (45 + 14) cm
= 2 (59) cm
= 118 cm
Therefore the length of the tape is 118 cm.
Answer:
The lid of a rectangular box of sides 45 cm and 15 cm is sealed all around with tape. The length of tape required is 120 cm
Step-by-step explanation:
To get the length of the tape required, we need to get the perimeter of the rectangular lid.
Perimeter of a rectangle is given by:
Perimeter = 2 (Length + Width)
In our case:
Length = 45 cm, Width = 15 cm
The perimeter of the rectangular lid is given by:
Perimeter = 2 (45 + 15)
= 2 × 60 cm = 120 cm
The length of the tape required to seal the tape is 120 cm.