Question

The lid of a rectangular box of sides to 40 cm by lo cm
is sealled all round with tape what is the length
of the tape required?​

Answer 1

Answer :

• 1m is the length of the tape required

Given :

• Length = 40cm
• Breadth = 10cm

To find :

• The length of the tape required

Solution :

As we know that,

• Perimeter of rectangle = 2(length + breadth)

Length of tape required = Perimeter of rectangle

》2(l + b)

》2(40 + 10)

》2(50)

》100cm

》1m = (1m = 100)

Hence , 1m is the length of the tape required

More Explanation:

• Perimeter of rectangle = 2(length + breadth)
• Area of rectangle = length × breadth
• Diagonal of rectangle = √(l² + b²)

Answer 2

Correct Question :-

• The lid of a rectangular box of sides to 40 cm by 10 cm is called all round with tape what is the length of the tape required?

Given :-

• Length = 40 cm
• Breadth = 10 cm

To find :-

• Find the Length of the tape required ?

★ $\large\underline{\frak{As\:we\: know\: that,}}$

$\large\dag$ Formula Used :

• $\boxed{\bf{Perimeter\:of\: rectangle\:=\:2(\: Length\: + \: Breadth\:)}}$

Solution :-

• Perimeter of tape required = Perimeter of reactangle

:$\implies$2( l + b )

$~~~~~$:$\implies$2( 40 + 10 )

$~~~~~~~~~~$:$\implies$2( 50 )

$~~~~~~~~~~~~~~~$:$\implies$100 cm

$~~~~~~~~~~~~~~~~~~~$:$\implies$1 m = (1m = 100)

$~~~~~~~~~~~~~~~~~~~~~~~~$:$\implies$${\underline{\boxed{\pink{\frak{1m~=~100}}}}}$★

$\large\dag$ Hence Verified !!

• $\large\underline{\rm{1~m}}$is the length of the tape required.