Question

The lid of arectangle box of sides 40 cm by 10 cm is sealed all round with tape. what is the length of the tape required.​

Answer 1

Answer:

• Total length of tape required = 100 cm.

Step By Step Explanation:

Given:

• The lid of Rectangle box of sides = 40 × 10.
• The box is sealed all round with tape.

To Find:

• Length of tape required.

Now, it is given:

=> Length of box = 40 cm

=> Breadth of box = 10 cm

Now, we know that.

=> Perimeter of box = 2(l + b)

=> Perimeter of box = 2(40 + 10)

=> Perimeter of box = 2(50)

=> Perimeter of box = 100 cm

Hence, Total length of tape required = 100 cm

Answer 2

AnSwEr :

$\mathfrak{Given} \begin{cases} \sf{Length \: of \: box \: = 40 \: cm} \\ \sf{Breadth \: of \:box \: = \: 10 \: cm} \end{cases} \\ \\ \bigstar {\underline{\sf{We \: have \: to \: find \: length \: of \: tape}}} \\ \\ \dashrightarrow \boxed{\tt{Perimeter \: = \: 2(length \: + \: breadth)}} \\ \\ \dashrightarrow \tt{Perimeter \: = \: 2(40 \: + \: 10)} \\ \\ \dashrightarrow \tt{Perimeter \: = \: 2(50)} \\ \\ \dashrightarrow \tt{Perimeter \: = \: 100} \\ \\ \underline{\boxed{\textsf{\textbf{Perimeter \: = \: 100 \: cm}}}} \\ \\ \underline{\sf{\therefore \: Length \: of \: Tape \: required \: is \:100 \: cm}}$

$\boxed{\begin{minipage}{7 cm}\underline{\tt{\textbf{Some Formulae Related to it :}}}\\ \\ \sf Perimeter of Rectangle = 2(length + Breadth) \\ \sf Area of Rectangle = length \times \: \sf Breadth \\ \sf Perimeter \: of \: Square = 4 \times \sf Side \\ \sf Area \: of \: Square = Side^2\end{minipage}}$