Question

the lid of rectangular box of side 40 cm by 10cm is sealed all round with tape what is a length of tape required? ​

Answer 1

Step-by-step explanation:

• FIRST ONE IS PERIMETER OF RECTENGAL = 2(L+B) =2(40+10)=2(50) =100

Answer 2

✦ Question :-

The lead of a rectangular box of side 40 cm by 10 metre is sealed all round with tape what is the length of the tape word?

Answer :-

$\red{\bigstar}$ Length [l]

$\huge\leadsto{\sf\purple{10 \: m}}$

Given :

Length of the rectangular box = 40 cm

Breadth of the rectangular box = 10 cm

Find :

Length = ?

Solution :-

According to the Question :-

Length of tape required = Perimeter of the rectangular box

So , Applying formula :-

Perimeter of rectangle = 2 ( l + b )

= 2 (40 + 10)

= 100 cm

Now , Converting it into cm

= 10m is the required answer .

Additional Notes :-

❥ Perimeter of Rectangle = 2( L + B )

❥ Perimeter of square = 4 × Side

❥ Perimeter of triangle = AB + BC + CA

❥ Area of Rectangle = L × B

❥ Area of Square = ( side ) ²

❥ Area of Rhombus = Product of Diagonal/2.

❥ Area of Parallelogram = Base × Height.

❥ Area of triangle = 1/2 × base × height .