Chemistry, asked by vanshmalhotra353, 1 year ago

The Ligand (A) in brown ring complex (B) is obtainable from a lead compound (C) with a dense liquid (D) which concerts salts (E) into acid {F) Give structure and reaction​

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Answered by Anonymous
0

In this compound, the nitrosyl ligand is positively charged, and iron is in a +1 oxidation state.

Now, iron has stable oxidation states +2 and +3. Nitrosyl, as a ligand, comes in many flavours, of which a negatively charged nitrosyl is one.

I see no reason why the iron doesn't spontaneously oxidise to +3 and reduce the NO to −1 to gain stability. But I don't know how to analyse this situation anyway. I think that there may be some nifty backbonding increasing the stability, but I'm not sure.

So, why is iron in +1 here when we can have a seemingly stable situation with iron in +3

Hope it helps uh.. ❤

Answered by itzsakshii
0

Answer:

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