Question

the light terms in the expression 2x square -7ab +2ab -5 are ​

Answer 1

Step-by-step explanation:

sin' A = a (x'cos 6 – y' sin 6) + b”(x'sin 6 + y cost)* – 2ab(x' cos 6 – y' sin 6)(x'sin 6 ... cross term we require 0 = (b” – a”) cost sin 6 + ab(sin”6 – cos' 6) cos A "a 2 -2.