the limiting value van't hoff factor of na2so4is
Answers
Explanation:
Limiting value of Van't Hoff factor of [K4Fe(CN)6] is 11. A . B . and [K4Fe(CN)6] gives 5 ions in solution so its Van't Hoff factor is 5.
PLS MARK AS BRAINLIST....
Answer:
In this types of questions, the molecules after the . (the dot) are not considered in the Vanthoff factor. It could be anything like, NH3, H2o,etc.
As, you have asked for the limiting value of the Vant Hoff's factor (i), we take @(alpha - in the formula) as 1, because the Na2SO4 has fully dissociated, i.e., every Na2SO4 molecule has turned into two Na+ ions and a SO4- ions.
Also, if asked for maximum value or there is no dissociation (also called as ionisation) value mentioned in the question, you have to take @ = 1.
Else, if dissociation value (aka degree of dissociation) given,
for e.g., as 40% then you would not put the percentage value in the above given formula, rather you put 0.4 (that is diving the percentage value given by 100).