The line 2x−y+1=0 is tangent to the circle at the point (2, 5) and the center of the circle lies on x−2y=4 . Then find the radius of the circle.
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Answer:
Given:
Tangent, T:2x−y+1=0
Slope of tangent, T to the circle is 2
The line joining the centre and the point of contact of tangent is perpendicular with the tangent.
Thus, slope of line OA=−
2
1
Equation of OA,
(y−5)=−
2
1
(x−2)
x+2y=12
∴ Intersection with x−2y=4 will give coordinates of centre which are (8,2)
∴r=OA=
(8−2)
2
+(2−5)
2
=3
5
Hence, option A.
solution
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